Find the principal value of: `sec^(-1)(2/(sqrt(3)))`

Explanation

To find the principal value of \( \sec^{-1}\left(\frac{2}{\sqrt{3}}\right) \), we will follow these steps:

### Step 1: Let \( y = \sec^{-1}\left(\frac{2}{\sqrt{3}}\right) \)
This means that by definition of the inverse secant function, we have:
\[ \sec(y) = \frac{2}{\sqrt{3}} \]

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