At `25^(@)C` and 760 mm of Hg pressure a gas occupies 600 mL volume. What will be its pressure at a height where temperature is `10^(@)C `and volume of the gas is 640 mL.

Explanation

To solve the problem, we will use the combined gas law, which states that:

\[ \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2} \]

Where:
- \(P_1\) = initial pressure
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