The force required to punch a hole of diameter 2 mm, will be (If a shearing stress `4xx10^(8)N//m^(2)`.)

The shearing strain produced in a block of metal subjected to a shearing stress of 10^(8)N//m^(2) is ( Modulus of rigidity eta=8 xx 10^(10)N//m^(2) )

The shearing strain produced in a block of metal subjected to a shearing stress of 10^(8)N//m^(2) is ( Modulus of rigidity eta=8 xx 10^(10)N//m^(2) )

A metal wire is observed to stretch by one part in a million when subjected to a stress of 8xx10^(4)N//m^(2) . The Young's modulus of the metal is

Calculate the force F needed to punch at 1.46 cm diameter hole in a steel plate 1.27 cm thick fig. The ultimates shear stress of steel is 3.45 xx 10^(8)Nm^(-2) .

Steel ruptures when a shear of 3.5xx10^(8)Nm^(-2) is applied. The force needed to punch a 1 cm diameter hole in a steel sheet 0.3 cm thick is nearly:

Calculate the force F needed to punch a 1.46 cm diameter hole in a steel plate 1.27 cm thick. The ultimate shear strength of steel is 345 MN//m^2.

How much force is required to produce an increase of 0.2 % in the length of a brass wire of diameter 0.6 mm (Young's modulus for brass =0.9 xx 10^(11) N//m^(2) )