Considering the Carnot cycle as applied to a liquid film, show that in an isothermal process the amount of heat required for the formation of a unit area of the surface layer is equal to `q = - T. d alpha//d T`,where `d alpha//d T` is the temperature derivative of the surface tension.

If the surface tension of liquid is T, the work required to increase, its surface area by A is

The surface of a soap film was increasedd isothermallly by Delta o at a temperature T . Knowing the surface tension of the soap water solution alpha and the temperature coefficient d alpha//d T , find the increment. (a) of the entropy of the film's surface layer , (b) of the internal energy of the surface layer.

Drops of liquid of density d are floating half immersed in a liquid of density p. If the surface tension of the liquid is T, then the radius of the drop is

A liquid drop of diameter D breaks upto into 27 small drops of equal size. If the surface tension of the liquid is sigma , then change in surface energy is

A ring of radius r, and weight W is lying on a liquid surface. If the surface tension of the liquid is T, then the minimum foce required to be applied in order to lift the ring up

P = excess pressure value of different curvatures, r – radius, d - diameter, T - surface Tension

A spherical liquid drop of radius R is split up ino 8 equal droplets .If T is the surface tension of the liquid , then the work done in this process is

If T is the surface tension of soap solution, the amount of work done in blowing a soap bubble from a diameter D to 2D is

If T is the surface tension of soap solution, the amount of work done in blowing a soap bubble from a diameter D to 2D is