int(dx)/(2cos x+3sin x)=

int(1)/(2cos x+ 3 sin x+4)dx=

If int(dx)/(cos2x+3sin^(2)x)=(1)/(a)tan^(-1)(b tanx)+c, then ab=

int (3 cos 3x-2 sin 2x)/(cos 2x+ sin 3x)dx=

int (3cos x+2 sin x)/(4 cos x+3 sin x)dx=

int (dx)/((cos ^(2)x-3sin^(2)x))=?

int dx/(cos2x+3sin^(2)x)

Evaluate: (i) int(e^(2x))/(e^(2x)-2)dx (ii) int(2cos x-3sin x)/(6cos x+4sin x)dx

int(2cos x)/(3sin ^(2)x)dx,

Find the mistake in the following evaluation of the integral I=int_0^pi(dx)/(1+2sin^2x) , then : I=int_0^pi(dx)/(cos^2x+3sin^2x) =int_0^pi(sec^2x dx)/(1+3tan^2x)=1/(sqrt(3))[tan^(-1)(sqrt(3)tanx)]_pi^0=0