Calculate the freezing point of an aqueous solution containing 10.50 g of `MgBr_(2) ` in 200 g of water (molar mass of `MgBr_(2) = 184`g. `K_(f)` for water = 1.86 K kg `mol^(-1)`)

Explanation

`Delta T_(f) = 7.5^(@)` C
`Delta T_(f) = iK_(f)`m
`T_(f)^(@) = 3 xx 1.86^(@) C kg "mol"^(-1)`
`xx (10.50 g )/(184 "g mol"^(-1)) xx (1000)/(200 kg)`
`0^(@) C - T_(f) = 1.59^(@)` C
`T_(f) = - 1.59^(@) `C or 271.41 K