In ac circuit contains a pure capacitor, across which an ac emf
`e = 100 sin (1000t)`, volt
is applied. If the peak value of the current is 200 mA, then the value of the capacitor is

When an alternating emf, e=300 sin 100pit volt is applied across a bulb, the peak value of current is found to be 2 A. the average power is

A 50muF capacitor, a 30Omega esistor and a 0.7 H inductor are connected in series to an a.c. supply which generates an emf .e. given by e = 300 sin (200 t) volt. Calculate peak value of the current flowing through the circuit.

Let f = 50 Hz, and C = 100 muF in an AC circuit containing a capacitor only. If the peak value of the current in the circuit is 1.57 A at t = 0. The expression for the instantaneous voltage across the capacitor will be

An a.c. emf of e=220 sin omega t is applied across the capacitor, the power consumption is

In an AC circuit , an alternating voltage e = 200 sin 100t V is connected to a capacitor of capacity 1mu F . The rms value of the current in the circuit is

In an ac circuit an alternating voltage e =200 sqrt2 sin 100 t volts is connected to capacitor of capacity 1 muF The r.m.s.value of the current in the circuit is :

In an ac circuit an alternating voltage e = 200 sqrt(2) sin 100t volts is connected to a capacitor of capacity 1 muF. The rms.value of the current in the circuit is