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GD and GH are respectively the bisectors...

GD and GH are respectively the bisectors of `angleACB and angleEGF` such that D and H lie on sides AB and FE of `DeltaABC and and DeltaEFG` respectively. If `DeltaABC~DeltaFEG` , show that:
`(CD)/(GH) =(AC)/(FG)`

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The correct Answer is:
`/_ DCB = /_ HGE`
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OSWAAL PUBLICATION-TRIANGLES-TEXTBOOK CORNER (EXERCISE 2.3)
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  9. In Fig , ABC and AMP are two right triangles, right angled at B and M...

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