The tangent to the curve `y=e^(2x)` at the point (0,1) meets X-axis at

Options

A. (1,0)
B. (2,0)
C. `(-1/2,0)`
D. `(1//2,0)`

Answer

C

Explanation

Equation of line passing through (0,1) and slope =2
`y-1 =2 (x-0)`
let line meets at (x,0)
Tangent to the curve at (0,1) meets the x axis at `((-1)/(2),0)`