`underset( x rarr (pi) /(2))("lim")( 1- sinx)/( cos x) ` या `underset( x rarr ( pi )/(2))("lim")( sec x - tan x )`

underset( x rarr 2^(+))("Lim")g(x)=

underset( x rarr 1 ) ("lim") (1-x)/( 1-x^(2))=

underset( x rarr (pi)/(4))("Lim")(1-tanx)/( 1- sqrt(2) sin x)

lim_ (x rarr (pi) / (2)) (sec x-tan x)

underset(x rarr 0)(lim) (2x)/(tan 2x) is

lim_ (x rarr (pi) / (2)) {(1-sin x) tan x}

underset( x rarr ( pi )/( 4))("Lim")(sqrt( 1- sqrt( sin x)))/(pi - 4x)

If l = underset( x rarr 0) ("Lim")( x ( 1+ a cos x ) - bsin x ) /( x^(3))= underset( x rarr 0 ) ("Lim") ( 1+a cos x ) /( x^(2))- underset( x rarr 0 ) ("lim")( b sin x )/( x^(3)) , where l in R , then

lim_ (x rarr (pi) / (2)) (sec x-tan x) / (pi-2x)

lim_(x rarr((pi)/(2)))(1-sin x)tan x=