An electron of mass `m_(e)` and a proton of mass `m_(p)` are moving with the same speed. The ratio of their de-Broglie wavelength `lamda_(e)//lamda_(p)` is

Options

A. 1
B. 1836
C. `1/1836`
D. 918

Answer

B

Explanation

de Broglie wavelength of a ball is `lamda = h/(mv)`
where m is the mass and v is the speed of the particle . As electron and proton both are moving with same . Speed therefore the ratio of their de Broglie wavelengths is
`(lamda_(e))/(lamda_p)=(m_p)/(m_e) =(1.67 xx10^(-27)kg)/(9.1 xx10^(-31)kg)~~1836`