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To divide a line segment AB in the ratio...

To divide a line segment AB in the ratio `5 : 6`, draw a ray AX such that `BAX` is an acute angle , drawn a ray BY parallel to AX with the points `A_(1) , A_(2), A_(3), ,… and B_(1), B_(2), B_(3) ,…` located at equal distances on ray AX and BY respectively. Then the points joined are

A

1)`A_5 and B_6`

B

2)`A_6 and B_5`

C

3)`A_4 and B_5`

D

4)`A_5 and B_4`

Text Solution

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The correct Answer is:
A
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