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Amphilbole silicate structure has 'x' nu...

Amphilbole silicate structure has 'x' number of corner shared per tetrahedron. The value of x is :

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Amphibole silicate structure has 'x' number of corner shared per tetrahedron. The value of 'x' is :

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The number of O-atoms that are shared per SiO_4 tetrahedra in silicate anion of beryl is-

Please help Sabu decode the jail lock. Chacha Choudhary gave Sabu a formula : f_(1) = ((x)/(z)xx y), f_(2) =((f)/(v) xxu), f_(3) = ((r)/(s)xx w) Sabu can open the lock if he finds the value of 3f_(1) +f_(2) +f_(3) = key where: Number of triangular faces in a truncated tetrahedron = x Number of hexagonal faces in a truncated tetrahedron = x Number of corners in a truncated tetrahedron = z Number of square faces in a truncated octahedron = t Number of hexagonal faces in a truncated octahedron = u Number of corners in a truncated octahedron = u Number of triangular faces in a truchcated cube = w Number of octangonal faces in a truncated cube = r Number of corners in a truncated cube = s What is the KEY ?

Total number of faces in a truncated octahedron=x Total number of faces in a truncated tetrahedron=y Then x+y is :

Silicon forms a very large number of compounds containing SiO_(4)^(4-) anion as the basic unit. The structure of this basic unit is a tetrahedron in which oxygen atoms are arranged tetrahedral around a silicon atom. The total number of oxygen shared per tetrahedron in Beryl [Be_(3)Al_(2)Si_(6)O_(18)]