Before equilibrium is set-up for the chemical reaction, `N_(2)O_(4)hArr 2NO_(2)`, vapour density of the gaseous mixture was measured. If D is the theoretical value of vapour density, variation of x with `D//d` is by the graph.

Before equilibrium is set-up the chemical reaction N_(2)O_(4)(g) hArr 2NO_(2)(g) , vapour density d of the gaseous mixture was measured. If D is the theoretica value of vapour density, variation of alpha with D//d is given by the graph below. What is value D//d at point A ?

Before equilibrium is set-up the chemical reaction N_(2)O_(4)(g) hArr 2NO_(2)(g) , vapour density d of the gaseous mixture was measured. If D is the theoretica value of vapour density, variation of alpha with D//d is given by the graph below. What is value D//d at point A ?

A mixture contains N_(2)O_(4) and NO_(2) in the ratio 2:1 by volume. The vapour density of the mixture is:

A mixture contains N_(2)O_(4) and NO_(2) in the ratio 2:1 by volume. The vapour density of the mixture is:

For the reaction N_(2)O(g) hArr 2NO_(2)(g). DeltaH=57.49kJ // mole, the vapour density of equilibrium mixture ……………………….. with increase of temperature.

For the reaction N_(2)O(g) hArr 2NO_(2)(g). DeltaH=57.49kJ // mole, the vapour density of equilibrium mixture ……………………….. with increase of temperature.

For the following equilibrium reaction N_(2)O_(4)(g)hArr 2NO_(2)(g) , NO_(2) is 50% of the total volume at a given temperature. Hence, vapour density of the equilibrium mixture is :

For the reaction N_2O_4 hArr 2NO_2(g) , if percentage dissociation of N_2O_4 are 20%, 45%, 65%, 80% then the sequence of observed vapour densities wil be :

For the reaction N_2O_4 hArr 2NO_2(g) , if percentage dissociation of N_2O_4 are 20%, 45%, 65%, 80% then the sequence of observed vapour densities wil be :

For the reaction N_2O_4 hArr 2NO_2 , if degrees of dissociation of N_2O_4 are 25%,50% and 100% , the gradation of observed vapour densities is