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A bullet is fired from gun. The force on...

A bullet is fired from gun. The force on bullet is, `F = 600-2xx10^(5)t` newton. The force reduces to zero just when bullet leaves barrel. Find the impulse imparted to bullet.

Text Solution

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`F=600-2xx10^(5)t`
F becomes zero as soon as the bullet leaves the barrel. `0=600-2xx10^(5)t , 600 = 2xx10^(5)t`
`t=3xx10^(-3)s` Impulse `= int_(0)^(1) Fdt`
`= int_(0)^(t)(600-2xx10^(5)t)dt=[600t-cancel(2)xx10^(5)(t^(2))/(cancel(2))]^(3xx10^(-3)`
`=600xx3xx10^(-3)-10^(5)xx9xx10^(-6)=0.9 Ns`
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