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Benzene burns according to the following...

Benzene burns according to the following equation at `300K (R=8.314J mol e^(-1)K^(-1))`
`2C_(6)H_(6)(l)+15O_(2)(g)rarr12CO_(2)(g)+6H_(2)O(l) " "DeltaH^(@)=-6542kJ //mol`
What is the `DeltaE^(@)` for the combustion of `1.5 mol` of benzene

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