Home
Class 12
PHYSICS
An iron tor suports N = 500 turns. Fin...

An iron tor suports `N = 500` turns. Find the magnetic field energy if a current `I = 2.0 A` preoduces a magnetic flux across the tore's cross-section equal to `Phi = 1.0 mWb`.

Promotional Banner

Similar Questions

Explore conceptually related problems

An iron core supports N turns. If a current i produces a magnetic flux across the Core's cross section equal to phi , then the magnetic field energy is _______ .

A circular iron, core supports N turns . If a current I produces a magnetic flux phi across the core's cross section, then then magnetic energy is :-

Find the energy stored in the magnetic field if current of 5A produces a magnetic flux of 2xx10^(-3) Wb through a coil of 500 turns.

If a magnetising field of 1600 A//m produces a magnetic flux of 14xx10^(-5) Wb in an iron bar of cross-sectional area 0.2 cm^(2) . Then,

What will be the magnetic moment when a current is passed through a current loop of N turns and the area of cross section is A?

An iron core shaped as a doughnut with round cross-section of radius a = 3.0 cm carreis a winding of N = 1000 turns through which a current I = 1.0 A flows. The mean radius of the doughnut is b = 32 cm . Using the polt in Fig. Find the magnetic energy strored up in the core. A field strength H is suposed to be the same throughout the cross-section and equal to its magnitude in the centre of the cross-section.

A solenoid is 3 m long and its inner diameter is 4.0 cm . It has three layers of windings of 2000 turns each and carries a current of 2.0 amperes. The magnetic flux for an cross-section of the solenoid is nearly

State the expression for the magnetic field due to a circular are of wire carrying a current I. Hence find the magnetic field at the centre of circular coil and having n turns.

An iron core shaped as a tore number of turns mean R = 250 mm . The supports a winding with the total number of turns N = 1000 . The core has a cross-cut of width b = 1.00 mm . With a current I = 0.85 A flowing through the winding, the magnetic induction in the gap is equal to B = 0.75 T . Assuming the scarttering of the magnetic flux at the grap edges to be negligible, find the permeaiility of iron under these conditions.

A magnetizing field of intensity 1600A//m produces a magnetic flux of 2.5 xx10^-5 Wb in a bar of iron of cross-section 0.2 cm^2 . The permeability of the bar is