[" If both "f(x)&g(x)" are differentiable functions "],[" at "x=x_(0)," then the function defined as,"h(x)=],[" Maximum "{f(x),g(x)}:]

If both f(x)&g(x) are differentiable functions at x=x_(0) then the function defiend as h(x)=Maximum{f(x),g(x)}

If both f(x) & g(x) are differentiable functions at x=x_0 then the function defiend as h(x) =Maximum {f(x), g(x)}

If both f(x) and g(x) are non-differentiable at x=a then f(x)+g(x) may be differentiable at x=a

If f(x)a n dg(f) are two differentiable functions and g(x)!=0 , then show trht (f(x))/(g(x)) is also differentiable d/(dx){(f(x))/(g(x))}=(g(x)d/x{f(x)}-g(x)d/x{g(x)})/([g(x)]^2)

If f(x) and g(f) are two differentiable functions and g(x)!=0, then show trht (f(x))/(g(x)) is also differentiable (d)/(dx){(f(x))/(g(x))}=(g(x)(d)/(pi){f(x)}-g(x)(d)/(x){g(x)})/([g(x)]^(2))

Let f ,g are differentiable function such that g(x)=f(x)-x is strictly increasing function, then the function F(x)=f(x)-x+x^(3) is

A function f(x) is differentiable at x=c(c in R). Let g(x)=|f(x)|,f(c)=0 then

If f(x) and g(x) are two differentiable functions, show that f(x)g(x) is also differentiable such that (d)/(dx)[f(x)g(x)]=f(x)(d)/(dx){g(x)}+g(x)(d)/(dx){f(x)}

Let f (x), g(x) be two real valued functions then the function h(x) =2 max {f(x)-g(x), 0} is equal to :