The equation of a line is given by `x=by+c, z=ay+d`, write it in cartesian form and vector form.

Intersection of two lines in cartesian form and vector form

The Cartesian equations of a line are x=a y+b ,z=c y+d Find its direction ratios and reduce it to vector form.

The Cartesian equations of a line are x=ay+b,z=cy+d. Find its direction ratios and reduce it to vector form.

The cartesian equation of a line is given by : 6x-1=3y+2=2x-2 . Find its direction ratios and reduce it to vector form.

Cartesian form OF line in 3D

Derive the equation of a plane in normal form both in the vector and Cartesian form .

The Cartesian equation of a line is (x-5)/3=(y+4)/7=(z-6)/2 , write its vector form.

If the equation of line is x = ay + b : z = cy +d. Then its symmetric form is

Consider the vector 2hati+2hatj-3hatk .Find the equation of line passing through A(3.4,5) and parallel to given vector , in the vector form and in the Cartesian form.

The Cartesian equations of a line are 6x -2 =3y +1 =2z-2 (a) Write these equations in standard form and find the direction cosines of the given line. ( b) Write down the Cartesian and vector equations of a line passsing through (2,-1,1) and parallel to the given line.