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Choosing a number related to a given num...

Choosing a number related to a given number in the same manner as the two numbers of another given pair are related to each other
48 : 122 :: 168 : ?

A

215

B

225

C

290

D

292

Text Solution

AI Generated Solution

The correct Answer is:
To solve the analogy problem \(48 : 122 :: 168 : ?\), we need to find a relationship between the first pair of numbers (48 and 122) and apply the same relationship to the second pair (168 and the unknown number). ### Step 1: Identify the relationship between 48 and 122 First, we can express 48 and 122 in terms of squares: - \(48 = 7^2 - 1\) (since \(7^2 = 49\) and \(49 - 1 = 48\)) - \(122 = 11^2 + 1\) (since \(11^2 = 121\) and \(121 + 1 = 122\)) ### Step 2: Analyze the relationship between the squares Now, we can observe the numbers \(7\) and \(11\): - The difference between \(11\) and \(7\) is \(11 - 7 = 4\). ### Step 3: Apply the same relationship to 168 Next, we need to find a number \(x\) such that: - \(168 = x^2 - 1\) To find \(x\): - Rearranging gives \(x^2 = 168 + 1 = 169\). - Taking the square root, we find \(x = 13\) (since \(13^2 = 169\)). ### Step 4: Determine the next number in the sequence Now, we need to find the next number using the same relationship: - The next number should be \(x + 4 = 13 + 4 = 17\). - We will calculate \(17^2 + 1\): - \(17^2 = 289\) - Therefore, \(17^2 + 1 = 289 + 1 = 290\). ### Conclusion The unknown number that corresponds to 168 in the analogy is \(290\). Thus, the answer is: \[ \text{?} = 290 \]

To solve the analogy problem \(48 : 122 :: 168 : ?\), we need to find a relationship between the first pair of numbers (48 and 122) and apply the same relationship to the second pair (168 and the unknown number). ### Step 1: Identify the relationship between 48 and 122 First, we can express 48 and 122 in terms of squares: - \(48 = 7^2 - 1\) (since \(7^2 = 49\) and \(49 - 1 = 48\)) - \(122 = 11^2 + 1\) (since \(11^2 = 121\) and \(121 + 1 = 122\)) ### Step 2: Analyze the relationship between the squares ...
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