consider :
Statement - I : `(p^^~q)^^(~p^^q)` is a fallacy .
Statement -II : `(prarrq)harr(~qrarr~p)` is a tautology .

Statement - I : (p ^^ ~ q) ^^ (~ p ^^ q) is a fallacy. Statement - II : (p rarr q) harr (~q rarr ~ p) is a tautology.

Consider : Statement I: (p^^~q)^^(~p^^q) is a fallacy Statement II: (ptoq)harr(~q to ~p) is a tautology

Consider : Statement I: (p^^~q)^^(~p^^q) is a fallacy Statement II: (ptoq)harr(~q to ~p) is a tautology

Consider : Statement I: (p^^~q)^^(~p^^q) is a fallacy Statement II: (ptoq)harr(~q to ~p) is a tautology

Statement-1 : ( p ^^ ~ q) ^^ (~ p ^^ q) is a facllocy. Statement -2: ( p to q) harr ( ~ q to ~ p) is a tautology .

Consider : Statement I : (phat~""q)hat(~""phatq) is a fallacy. Statement II : (pvecq)harr(~""qvec~""p) is a tautology. (1) Statement - I is True; Statement -II is true; Statement-II is not a correct explanation for Statement-I (2) Statement -I is True; Statement -II is False. (3) Statement -I is False; Statement -II is True (4) Statement -I is True; Statement -II is True; Statement-II is a correct explanation for Statement-I

Statement I : (p^^∼q)∧(∼p^^q) is a fallacy. Statement II : (p→q)↔(∼q→∼p) is a tautology.