Calculate the ratio of number of pure and hybrid orbitals used for bonding in an acetylene molecule

Explanation

Acetylene has two .C. atoms and two .H.atoms. Carbon undergoes sp hybridisation
Number of hybrid orbitals = 2 `xx` 2 = 4
Number of pure orbitals = 4 (from C) + 2 (from H) = 6
Ratio of number of pure and hybrid orbitals = 4:6 = 2:3