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For the following cell Zn//Zn^(2+) // Cd...

For the following cell `Zn//Zn^(2+) // Cd^(2+) // Cd `
`E_("cell") = 0.30V` and `E_("cell")^@ = 0.36V`. Then the value of `[Cd^(2+)]//[Zn^(2+)]` is

A

10

B

1

C

0.1

D

0.01

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The correct Answer is:
D
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AAKASH SERIES-REVISION EXERCISE -ELECTROCHEMISTRY
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