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int log (2- 3x) dx =...

`int log (2- 3x)` dx =

A

`(x- (2)/(3)) `log |2 -3x| - x +c

B

(x -2) log |2- 3 x | + 3x + c

C

`(1)/(3) `(x -2) log | 2- 3x | -3x + c

D

`(1)/(3)` (x -2) log |2-3x| - 3x + c

Text Solution

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The correct Answer is:
A
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