A stone is thrown up vertically and the height x ft it reached in t seconds is `x=(80)t -(16)t^(2)`. It reached the maximum height in time `t=`

A stone is thrown up vertically. The height it reaches at time t seconds is given by x=80t-16t^(2) . The stone reaches the maximum height in time t seconds is given by

A stone is thrown vertically up and the height s reached in time t is given by s=80t-16t^2 . The stone reaches the maximum height in time t =

A stone is thrown up vertically and the height x feet reached by it in time t seconds is given by x=80t-16t^(2) . The stone reaches the maximum height in time (seconds)

A stone is thrown vertically upwards and the height x ft, reached by the stone in t seconds is given by x=80t-16t^(2) . The stone reaches the maximum height in

A stone thrown vertically upwards satisfies the equations s = 80t –16t^(2) . The time required to reach the maximum height is

A stone is projected vertically upwards. Its height h at time t sec is h=(80)t-(16)t^(2) . The velocity with which it hits the ground is

A stone thrown vertically upwards rises S ft in t seconds where S =112t-16t ^(2) . The maximum height reached by the stone is

A ball is thrown vertically upwards which satisfies the equation S=80t-16t^2 . Find the time required to reach the maximum height.