2% of aqueous urea and 6% of aqueous 'X' are isotonic. If 'X' is a molecular solid, calculate its molar mass.

Explanation

For isotonic solutions, osmotic pressures are same, `pi_1=pi_2`
Hence, concentrations of solutions are also same, `C_1=C_2`
Since moles are equal , `W_1/M_1=W_2/M_2` (or) `2/60=6/M_2`
Molar mass of solute X=`M_2="180 g mol"^(-1)`