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Bond energies of H(2),Cl(2) and HCl are ...

Bond energies of `H_(2),Cl_(2)` and `HCl` are respectively `"104, 58 and 103 k cal mol"^(-1)`. Calculate Pauling's electronegativity of chlorine. 

Text Solution

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Average of bond energies of `H_2` and `Cl_2` is the calculated bond energy of `HCl = (104 + 58)/(2)`
`= 81 K cal mol^(-1)`
Experimental bond energy of `HCl = 100 k cal mol^(-1)`
`Delta -` Bond (resonance ) stabilisation energy = 100- 81 = 19 k cal `mol^(-1)`
`X_1 - X_2 = 0.208 sqrt(Delta) = 0.208 sqrt(19)`
`= 0.208 xx 4.35 = 0.90`
Since Pauling.s electronegativity of hydrogen is 2.1 that of chlorine `=2.1 + 0.9 = 3.0`
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