An electron and a proton are accelerated through the same potential. Which one of the two has (i)b greater value of de-Broglie wavelength associated with it and (ii) less momentum?justify your answer.

Explanation

To solve the problem, we need to analyze the de-Broglie wavelength and momentum of both the electron and proton when they are accelerated through the same potential.

### Step-by-Step Solution:

1. **Understanding de-Broglie Wavelength**:
The de-Broglie wavelength (\( \lambda \)) is given by the formula:
\[
\lambda = \frac{h}{\sqrt{2mqV}}
...