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If the area enclosed by the curve y=sqrt...

If the area enclosed by the curve `y=sqrt(x)` and `x=-sqrt(y)` , the circle `x^2+y^2=2` above the x-axis is `A ,` then the value of `(16)/piA` is___

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CENGAGE ENGLISH-APPLICATION OF INTEGRALS-All Questions
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  11. Find the area lying in the first quadrant and bounded by the curve y=x...

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