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Solve (x^2-2x-3)/(x+1)=0....

Solve `(x^2-2x-3)/(x+1)=0.`

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Equation `(x^(2)-2x-3)/(x + 1) = 0` is solveble over R - {-1}
Now, `(x^(2)-2x-3)/(x + 1) = 0`
or `x^(2)-2x -3 = 0 or (x - 3)(x+1)= = 0`
or `x = 3 only (as x `in` R - {-1})`
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