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Find the equation of the tangent to the curve `y=(x-7)/((x-2)(x-3)` at the point where it cuts the x-axis.

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Given, equation of curve is `y=(x-7)/((x-2(x-3)` .........(1)
To find the intersection of given curve with x-axis
Put `y=0` in `eq(1)` we get
`0=(x-7)/((x-2(x-3)`
...
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