A capacitor having a capacitance of `100 mu f` is changed to a potential difference of `50V.`(a) What is the magnitude of the charge on each plate? (b)The charging battery is disconnected and a dielectric of dielectric constant 2.5 is inserted . Calculate the new potential difference between the plate .

Explanation

To solve the problem step by step, we will break it down into two parts as given in the question.

### Part (a): Finding the Magnitude of the Charge on Each Plate

1. **Identify the Given Values:**
- Capacitance, \( C = 100 \, \mu F = 100 \times 10^{-6} \, F \)
- Potential difference, \( V = 50 \, V \)

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