A gaseous hydrocarbon when burns in oxygen gives 3.38g CO_(2) , 0.690g water and no other product.At STP,volume of 10L of this hydrocarbon is found to weigh 11.6g .What will be the molecular mass of the hydrocarbon.
Hydrocarbons - Reactions Of Alkynes 2
Hydrocarbons - Preparation Of Alkenes 2
When one of the following hydrocarbon is burnt in excess of oxygen, the volume of CO_(2) evolved is just three times to that of hydrocarbon taken. The hydrocarbon is
1 mole of hydrocarbon on complete combustion give 4 mole of CO_(2) . Calculate no of carbon in hydrocarbon.
0.20 g of hydrocarbon on combustion gave 0.66 g CO_2 . The percentage of hydrogen in the hydrocarbon is about
10 ml of hydrocarbon requries 55 ml of oxygen for complete combustion producing 40 ml of CO_(2) . The formula of the hydrocarbon is:
1 litre of a hydrocarbon weight as much as one litre of CO_(2) . The moleecular formula of hydrocarbon is :-
10mL of gaseous hydrocarbon on combustion gives 40ml of CO_(2)(g) and 50mL of H_(2)O (vapour) The hydrocarbon is .
