A vessel contains 8 gm of air at 400K. Some amount of air leaks out through the hole provided to it. After some time, the pressure is halved and the temperature is changed to 300 K. Find the mass of the air escaped.
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According to the gas equation, `P_(1)/(m_(1)T_(1))=P_(2)/(m_(2)T_(2))" "m_(2)=P_(2)/P_(1)xxT_(1)/T_(2)xxm_(1)` = `1/2xx4/3xx8=16/3=5.33` `thereforem_(2)=5.33gm` `rArr` Massof the gas escaped = `m_(1)-m_(2)` = 8 - 5.33 = 2.67 gm
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