Identify the products X and Y formed in the following reaction.
`CH_3-CH_2-CH=CH-CH_3+HCl = X+Y`

Options

A. a. `X=CH_3CH_2CH_2CH_2CH_2Cl`,
`Y=CH_3CH_2-underset(Cl)underset(|)(CH)-CH_2CH_3`
B. b. `X=CH_3CH_2-underset(Cl)underset(|)(CH)-CH_2CH_3, Y=CH_3CH_2CH_2-underset(Cl)underset(|)(CH)-CH_3`
C. c.`X=CH_3CH_2-underset(Cl)underset(|)(CH)-CH_2CH_3, Y=CH_3-underset(Cl)underset(|)(CH)-underset(Cl)underset(|)(CH)-CH_2CH_3`
D. d.`X=ClCH_2-CH_2-CH=CH-CH_3, Y=CH_3CH_2-CH=CH-CH_2Cl`

Answer

To solve the problem of identifying the products X and Y formed in the reaction of pent-2-ene with HCl, we can follow these steps:

### Step-by-Step Solution

1. **Identify the Reactant**: The given reactant is pent-2-ene, which has the structure:
\[ CH_3-CH_2-CH=CH-CH_3 \]
This indicates that there is a double bond between the second and third carbon atoms in a five-carbon chain.

2. **Understand the Reaction Type**: The reaction involves the addition of hydrogen chloride (HCl) to the alkene. This is an electrophilic addition reaction.

3. **Apply Markovnikov's Rule**: According to Markovnikov's rule, when HX (where X is a halogen) adds to an unsymmetrical alkene, the hydrogen atom (H) will attach to the carbon with the greater number of hydrogen atoms (the less substituted carbon), and the halide (Cl) will attach to the more substituted carbon.

4. **Identify the Substituted Carbons**: In pent-2-ene:
- The double bond is between C2 and C3.
- C2 (left side of the double bond) has two hydrogen atoms and is less substituted.
- C3 (right side of the double bond) has one hydrogen atom and is more substituted.

5. **Determine the Major Product (X)**:
- According to Markovnikov's rule, Cl will attach to C3 and H will attach to C2.
- The structure of the major product (X) will be:
\[ CH_3-CH_2-CH(Cl)-CH_2-CH_3 \]
This can be named as 3-chloropentane.

6. **Determine the Minor Product (Y)**:
- The minor product (Y) is formed by the anti-Markovnikov addition, where Cl attaches to the less substituted carbon (C2) and H attaches to the more substituted carbon (C3).
- The structure of the minor product (Y) will be:
\[ CH_3-CH(Cl)-CH_2-CH_2-CH_3 \]
This can be named as 2-chloropentane.

7. **Final Products**:
- Major product (X): 3-chloropentane
- Minor product (Y): 2-chloropentane

### Summary of Products
- **X**: 3-chloropentane
- **Y**: 2-chloropentane