Match the column I with column II and mark the appropriate choice.
`{:("Column I","Column II"),((A) "Borax",(i) Na_(3)AIF_(6)),((B) "Inorganic benzene",(ii) Na_(2)B_(4)O_(7).10H_(2)O),((C )"Cryolite",(iii) AI_(2)O_(3).2H_(2)O),((D)"Bauxite",(iv) B_(3)N_(3)H_(6)):}`

Options

A. (A) `to` (ii), (B) `to` (iv), (C ) `to` (i), (D) `to` (iii)
B. (A) `to` (i), (B) `to` (ii), (C ) `to` (iii), (D) `to` (iv)
C. (A) `to` (ii), (B) `to` (iii), (C ) `to` (i), (D) `to` (vi)
D. (A) `to` (iii), (B) `to` (i), (C ) `to` (ii), (D) `to` (iv)

Answer

To solve the problem of matching Column I with Column II, we will analyze each item in Column I and find its corresponding chemical formula in Column II.

### Step-by-Step Solution:

1. **Identify Borax**:
- Borax is commonly known as Sodium Tetraborate Decahydrate.
- The chemical formula for Borax is \( \text{Na}_2\text{B}_4\text{O}_7 \cdot 10 \text{H}_2\text{O} \).
- Therefore, Borax (A) matches with (ii) \( \text{Na}_2\text{B}_4\text{O}_7 \cdot 10 \text{H}_2\text{O} \).

2. **Identify Inorganic Benzene**:
- Inorganic benzene refers to Borazine.
- The chemical formula for Borazine is \( \text{B}_3\text{N}_3\text{H}_6 \).
- Thus, Inorganic Benzene (B) matches with (iv) \( \text{B}_3\text{N}_3\text{H}_6 \).

3. **Identify Cryolite**:
- Cryolite is used in the extraction of aluminum and has the formula \( \text{Na}_3\text{AlF}_6 \).
- Therefore, Cryolite (C) matches with (i) \( \text{Na}_3\text{AlF}_6 \).

4. **Identify Bauxite**:
- Bauxite is an ore of aluminum and its formula is \( \text{Al}_2\text{O}_3 \cdot 2 \text{H}_2\text{O} \).
- Hence, Bauxite (D) matches with (iii) \( \text{Al}_2\text{O}_3 \cdot 2 \text{H}_2\text{O} \).

### Final Matching:
- (A) Borax → (ii) \( \text{Na}_2\text{B}_4\text{O}_7 \cdot 10 \text{H}_2\text{O} \)
- (B) Inorganic Benzene → (iv) \( \text{B}_3\text{N}_3\text{H}_6 \)
- (C) Cryolite → (i) \( \text{Na}_3\text{AlF}_6 \)
- (D) Bauxite → (iii) \( \text{Al}_2\text{O}_3 \cdot 2 \text{H}_2\text{O} \)

### Conclusion:
The correct option is **(A) → (ii), (B) → (iv), (C) → (i), (D) → (iii)**.