KUMAR PRAKASHAN|Exercise PRACTICE PAPER ( SECTION -D)|2 Videos
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A particle is projected in x-y plane with y- axis along vertical, the point of projection being origin. The equation of projectile is y = sqrt(3) x - (gx^(2))/(2) . The angle of projectile is ……………..and initial velocity is ………………… .
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KUMAR PRAKASHAN-APPLICATION OF DERIVATIVES -PRACTICE PAPER - 6 (SECTION - D)