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Using the data given below find out the ...

Using the data given below find out the strongest reducing agent.
`E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(Theta)=1.33V,E_(Cl_(2)|Cl^(-))^(Theta)=1.36V`
`E_(MnO_(4)^(-)|Mn^(2+))^(Theta)=1.51V,E_(Cr^(3+)|Cr)^(Theta)=-0.74V`

A

`Cl^(-)`

B

`Cr`

C

`Cr^(3+)`

D

`Mn^(2+)`

Text Solution

Verified by Experts

The correct Answer is:
B
The standard reduction electrode potential of `E_(Cr^(3+)|Cr)^(Theta)=-0.74V` is very less value (Highly negative).
So Cr is strong reducing agent.
`Cr to Cr^(3+) +3e^(-)`
* Cr easily oxidize and hence it is strong reducing in nature. `Mn^(2+) lt Cl^(-) lt Cr^(3+) lt Cr`.
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Given E_("Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V Among the following, the strongest reducing agent is E_(Cr^(3+)//Cr)^(@)=-0.74V^(x),E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V E_(Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(Cl//Cl^(-))^(@)=1.36V Based on the data given above strongest oxidising agent will be