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A steel wire of length 2 m and cross sec...

A steel wire of length 2 m and cross sectional area `2 mm^2` is fixed at one end and stretched by suspending a block of mass 2 kg on the surface of the moon. If the Young's modulus of steel is `2 xx 10^11 N m^(-2)` find the increase in the length of the steel wire. (g on the moon = 1/6 of the g on the earth)

Text Solution

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`L = 2m, A=2mm^(2)=2xx10^(-6)m^(2)`,
`M=2kg`, g on the moon `=(g)/(6)=(9.8)/(6)ms^(-2)`
`Y=2xx10^(11)(N)/(m^(2)), e=?`
The increases in length,
`e=(FL)/(AY) =(MgL)/(AY)=(2xx9.8xx2)/(6xx2xx10^(-6)xx2xx10^(11))`
`=1.633xx10^(-5)m`
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