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ABCDEF is a regular hexagon. bar(AB)+b...

ABCDEF is a regular hexagon.
`bar(AB)+bar(AC)+bar(AD)+bar(EA)+bar(FA)=`

A

`3bar(AB)`

B

`4bar(AB)`

C

`bar(AB)`

D

`2bar(AB)`

Text Solution

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The correct Answer is:
B
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AAKASH SERIES-PROPERTIES OF VECTORS-EXERCISE - II
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