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Cards on which numbers 1, 2, 3 ............

Cards on which numbers 1, 2, 3 .......... 100 are written (one number on one card and no number is repeated), put in a bag and are mixed thoroughly. A card is drawn at random from the bag. Find the probability that card taken out has
What is the probability that card taken out has a two digit odd number ?

A

0.23

B

0.45

C

0.56

D

0.34

Text Solution

AI Generated Solution

The correct Answer is:
To find the probability that a card drawn from a bag containing cards numbered from 1 to 100 has a two-digit odd number, we can follow these steps: ### Step 1: Identify the total number of cards The total number of cards is equal to the total numbers from 1 to 100. Therefore, the total number of cards is: \[ \text{Total cards} = 100 \] ### Step 2: Identify the two-digit odd numbers Next, we need to find the two-digit odd numbers between 1 and 100. The two-digit numbers range from 10 to 99. The odd numbers in this range can be listed as follows: - The first two-digit odd number is 11. - The last two-digit odd number is 99. The sequence of two-digit odd numbers is: \[ 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49, 51, 53, 55, 57, 59, 61, 63, 65, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 97, 99 \] ### Step 3: Count the two-digit odd numbers To count the two-digit odd numbers, we can observe that they form an arithmetic sequence where: - The first term \( a = 11 \) - The common difference \( d = 2 \) - The last term \( l = 99 \) To find the number of terms \( n \) in this sequence, we can use the formula for the nth term of an arithmetic sequence: \[ l = a + (n-1)d \] Substituting the values: \[ 99 = 11 + (n-1) \cdot 2 \] \[ 99 - 11 = (n-1) \cdot 2 \] \[ 88 = (n-1) \cdot 2 \] \[ n-1 = 44 \] \[ n = 45 \] Thus, there are 45 two-digit odd numbers. ### Step 4: Calculate the probability The probability \( P \) of drawing a two-digit odd number is given by the ratio of the number of favorable outcomes (two-digit odd numbers) to the total number of outcomes (total cards): \[ P(\text{two-digit odd number}) = \frac{\text{Number of two-digit odd numbers}}{\text{Total number of cards}} = \frac{45}{100} \] Simplifying this fraction: \[ P(\text{two-digit odd number}) = 0.45 \] ### Final Answer The probability that the card drawn has a two-digit odd number is: \[ \boxed{0.45} \]

To find the probability that a card drawn from a bag containing cards numbered from 1 to 100 has a two-digit odd number, we can follow these steps: ### Step 1: Identify the total number of cards The total number of cards is equal to the total numbers from 1 to 100. Therefore, the total number of cards is: \[ \text{Total cards} = 100 \] ...
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