An object of mass 3 kg is at rest . Now a force `F=6t^(2)hati+2thatj` is applied on the object . Find the velocity of the object at t=3 sec.

Explanation

Impulse `=int_(0)^(3) F dt =int_(0)^(3) (6t^(2)hati+2thatj) dt =[2t^(3)hati+t^(2)hatj]_(0)^(3) =54hati+9hatj`
Impulse= change in linear momentum
`54hati+9hatj=(vecv-vecu), 54hati+9hatj=3(vecv-vec0), vecv=(18hati+3hatj)m//s`