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Two sides of a Rhombus ABCD are paralle...

Two sides of a Rhombus ABCD are parallel to the line x-y=5 and 7x-y=3. The diagonals intersect at (2,1) then the equation of the diagonal are

A

x-y=1, 7x-y=13

B

x+y=3,x+7y=9

C

x+2y=4,2x-y=3

D

3x+4y=10,4x-3y=5

Text Solution

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The correct Answer is:
C
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