The distance between the electrodes of a conductivity cell is 0.98 cm and area of cross section of theeletrodeis `1.3cm^2`. Calculate the cell constant for the cell.

a conductivity cell, the distance between two electrodes is 0.62 cm and the area of cross section of the electrode is 1.15 cm^2 . Find the cell constant of the cell.

A conductivity cell dipped in 0.0005 M NaCl gives at 25^@C resistance of 13710 ohms.If the electrode of the conductivity cell are 0.7 cm apart and the area of cross section of the electrode is 0.82cm^2 ,what is the molar conductivity of the solution at 25^@C ?

A conductivity cell has two electrodes 50 mm apart and of cross section area 2.5 cm^2 . Find the cell constant.

The electrodes of a conductivities cell are 3 cm apart and have a cross-sectional area of 4 cm^(2) . The cell constant of the cell (in cm^(-1) ) is _________

Two electrodes are fitted in conductance cell 1.5 cm apart while the area of cross-section of each electrode is 0.75 cm^(2) . The cell constant is

Two similar wires under the same load yield elongation of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm^(2) , then the area of cross-section of the second wire is

In biprism experiment the distance between the two virtual images of the slit is 0.1 cm and the distance between the slit and biprism is 1 m .If the band width is 0.058 cm , calculate the wavelength of light .

Sikver crystallizes in fcc structure with edge length of unit cell, 4.07 xx 10^(-8) cm and if density of metallic silver is 10.5g cm^(-3) . Calculate the molecular mass of silver.

Face centred cubic crystal lattice of copper has density of 8.966 g cm^(-3) . Calculate the volume of the unit cell.