A particle of mass `m=1kg` is projected with speed `u=20sqrt(2)m//s` at angle `theta=45^(@)` with horizontal find the torque of the weight of the particle about the point of projection when the particle is at the highest point.

Explanation

To find the torque of the weight of the particle about the point of projection when the particle is at the highest point, we can follow these steps:

### Step 1: Understand the Problem
We need to calculate the torque (τ) of the weight of a particle (mass m = 1 kg) projected at an angle θ = 45° with an initial speed u = 20√2 m/s when the particle reaches its highest point.

### Step 2: Identify the Weight of the Particle
The weight (W) of the particle can be calculated using the formula:
\[ W = mg \]
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