A block of mass `1kg` is kept on smooth floor of a truck. One end of a spring of force constant `100 N//m` is attached to the block and other end is attached to the body of truck as shown in the figure. At `t = 0`, truck begins to move with constant acceleration `2 m//s^(2)`. The amplitude of oscillation of block relative to the floor of truck is

Options

A. `(a)0.06m`
B. `(b)0.02m`
C. `(c)0.04m`
D. `(d)0.03m`

Answer

B

Explanation

Let `x_(0)` is the compression in equilibrium. Then,
`kx_(0) = ma`
`x_(0) = (ma)/(k) = (1 xx 2)/(100)`
`= 0.02m`
Amplitude `= x_(0) = 0.02m`