Home
Class 12
PHYSICS
A conductor of length l is placed perpen...

A conductor of length `l` is placed perpendicular to a horizontal uniform magnetic field `B`.Suddenly, a certain amount of charge is passed throgh it, when it is found to jump to a height `h`. The amount of charge that passes through the conductor is

A

`(msqrt(gh))/(Bl)`

B

`(msqrt(ht))/(2Bl)`

C

`(msqrt(2gh))/(Bl)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
Linera impulse =mv
or `F/_\t=msqrt(2gh) or (ilB) /_\t=musqrt(2gh)`
But `i/_\t=/_\q`
`:. (/_\q)(lB)=msqrt(2gh)`
`Hence /_\q=(msqrt(2gh))/(BI)`
Promotional Banner

Topper's Solved these Questions

  • MAGNETICS

    DC PANDEY ENGLISH|Exercise MCQ_TYPE|1 Videos

  • MAGNETICS

    DC PANDEY ENGLISH|Exercise Exercise|160 Videos

  • MAGNETIC FIELD AND FORCES

    DC PANDEY ENGLISH|Exercise Medical entrance s gallery|59 Videos

  • MAGNETISM AND MATTER

    DC PANDEY ENGLISH|Exercise Medical gallery|1 Videos