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A charged particle moving along +ve x-di...

A charged particle moving along +ve x-direction with a velocity v enters a region where there is a uniform magnetic field `B_0(-hat k), from x=0 to x=d.` The particle gets deflected at an angle `theta` from its initial path. The specific charge of the particle is

A

`(Bd)/(vcostheta)`

B

`(vtantheta)/(Bd)`

C

(Bsintheta)/(vd)`

D

`(vsintheta)/(Bd)`

Text Solution

Verified by Experts

The correct Answer is:
D


`sintheta=d/r=d/((mv/Bq))=q/m=(vsintheta)/(Bd)`
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