A stone is thrown with a speed of `10 ms^(-1)` at an angle of projection `60^(@)`. Find its height above the point of projection when it is at a horizontal distance of 3m from the thrower ? (Take `g = 10 ms^(-2)`)

Explanation

To solve the problem step by step, we will use the equation of trajectory for projectile motion.

### Step 1: Identify the given values
- Initial speed (u) = 10 m/s
- Angle of projection (θ) = 60°
- Horizontal distance (x) = 3 m
- Acceleration due to gravity (g) = 10 m/s²

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