A battery of emf 2 V and internal resistance r is connected in series with a resistor of `10Omega` through an ammeter of resistance `2Omega`. The ammeter reads 50 mA. Draw the circuit diagram and calculate the value of r.

A battery of emf 1.4 V and internal resistance 2 Omega is connected to a resistor of 100 omega resistance through an ammeter. This resistance of the ammeter is 4//3 Omega . A voltmeter has also been connected to find the potential difference across the resistor. a. Draw the circuit diagram. b. The ammeter reads 0.02 A . What is the resistance of the voltmeter? c. The voltmeter reads 1.1 V . What is the error in the reading?

A battery of emf 2V and internal resistance 0.5(Omega) is connected across a resistance 1.5(Ω). Find the current flow through battery ?

A cell of e.m.f. 1.8 V and internal resistance 2 Omega is connected in series with an ammeter of resistance 0.7 Omega and a resistor of 4.5 Omega as shown in Fig. What would be the reading of the ammeter ?

A cell of e.m.f. 1.5 V, internal resistance 1 Omega is connected to the resistors of 4 Omega and 20 Omega in series. Draw a circuit diagram and calculate : the voltage drop when the current is flowing.

(A) : An ammeter is connected in series in the circuit. (R) : An ammeter is a high resistance galvanometer.

An ammeter with resistance R_A is connected in series with a resistor R, a battery of emf c and internal resistance r . The current measured by the ammeter is I_A . Find the current through the circuit if the ammeter is removed so that the battery and the resistor form a complete circuit. Express your answer in terms of I_A, r, R_A and R . Show that more "ideal" the ammeter, the smaller the difference between this current and the current I_A . ltbr. (b) If R = 3.80 Omega, epsilon = 7.50 V and r = 0.45 Omega , find the maximum value of the ammeter resistance R_A so that I_A is within 99% of the current in the circuit when the ammeter is absent. (c) Explain why your answer in part (b) represents a maximum value.

Three identical cells, each of emf 2 V and internal resistance 0.2Omega are connected in series to an external resistor of 7.4Omega . Calculate the current in the circuit.

A battery of e.m.f. 15 V and internal resistance 3 Omega is connected to two resistors 3 Omega and 6 Omega connected in parallel. Find : the current through the battery,

A battery of emf 15 V and internal resistance of 4Omega is connected to a resistor. If the current in the circuit is 2A and the circuit is closed. Resistance of the resistor and terminal voltage of the battery will be

A cell of e.m.f. 1.5 V, internal resistance 1 Omega is connected to the resistors of 4 Omega and 20 Omega in series. Draw a circuit diagram and calculate : the p.d. across each resistor